Syms dependent on time vector notation

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Tobias
Tobias el 12 de Oct. de 2020
Comentada: Tobias el 12 de Oct. de 2020
Hi!
I want to caculate the partial derivatives of a vector u:
syms A theta(t) phi(t);
u = [A*cos(phi)*theta;sin(phi)*phi];
du = diff(u,t);
Now u and du are converted to 1x1 symfun functions, but I actually want it to be a vector output as well.
I got this output for du:
A*cos(phi(t))*diff(theta(t), t) - A*sin(phi(t))*theta(t)*diff(phi(t), t)
sin(phi(t))*diff(phi(t), t) + cos(phi(t))*phi(t)*diff(phi(t), t)
But I want the output to be in 2x1 vector form. Does someone maybe know how to do this?
Thanks!

Respuesta aceptada

madhan ravi
madhan ravi el 12 de Oct. de 2020
formula(du)

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