How to remove zeroes not defined by indices

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Suraj
Suraj on 5 Nov 2020
Edited: Suraj on 6 Nov 2020
Hello All,
I have a large signal data file (about 3000000x1 double) and I first ran these values under a defined signal range and replaced the non conforming values to zero.
However, some of the values of the original data also contain zeroes for which I have the corresponding indices.
  1. How do I remove the other zeroes from the data but keep the zeroes corresponding to the indices?
Eg: 1. A = [ 1 2 0 0 3 0 4 0 5 6 0 9] -> Data
B = [3,6,8] -> Indices corresponding to the zeroes in A
Expected Output: [1 2 0 3 0 4 0 5 6 9]
Below is a code snippet for this logic that I tried but without success.
%Thr = Measured Data Signal (Appox. 3000000 x 1 double)
%idx = Indices for zeros to be retained in data signal
Thr2 = zeros(size(Thr));
Thr3 = Thr;
for k = 1:numel(idx)
Thr2(idx(k)) = idx(k);
end
for k1 = 1:numel(Thr)
if((Thr(k1)== 0)&&(k ~= Thr2(k)))
Thr3(k1) = [];
else
Thr3(k1) = Thr3(k1);
end
end
Any help would be appreciated.
Cheers!
  2 Comments
Suraj
Suraj on 5 Nov 2020
Hello Madhan,
In the example, B corresponds to the indices of the values that are equal to zero and that which need to be retained.
Therefore, only the zeroes that are present in the index values 3,6,8 need to be retained and the other zeroes (In indices 4, 11] need to be removed.
Thanks!

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Accepted Answer

madhan ravi
madhan ravi on 5 Nov 2020
Edited: madhan ravi on 5 Nov 2020
Wanted = zeros(numel(nonzeros(A)) + numel(B), 1);
Wanted(setdiff(1 : numel(Wanted), B)) = nonzeros(A)
  3 Comments
Suraj
Suraj on 6 Nov 2020
Perfect! Thanks for your help Madhan!

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