MATLAB Answers

Non-linear coupled ODE system of equations

1 view (last 30 days)
Panagiota Atzampou
Panagiota Atzampou on 1 Feb 2021
Answered: Jon on 1 Feb 2021
I want to solve the following set of coupled ODEs:
I went ahead and used the following assumptions: [ y(1)=θ(t), y(2)=d(θ(t))/dt ,y(3)=φ(t) and y(4)=d(φ(t))/dt ] in order to later on employ the ode45 command to find the solution. Eventhough the script I made runs with no errors or issues, the output matrix y is filled with NaN (except the first row of course, which corresponds to the initial conditions given).
Could you please help me pin point the error in my code, or alternatively propose another method perhaps more suitable to solve these equations?
Thank you in advance!
Here's the script:
% Definition of Parameters
g=9.81; % m/s2
l= input('Strings length: ');
Ttot=input('Total Simulation Time (sec): ');
% Initial Conditions
theta_0 = input('Theta_0 (in form of n*pi): ');
theta_t0 = input('Theta_t0: ');
phi_0 = input('Phi_0 (in form of n*pi): ');
phi_t0 = input('Phi_t0: ');
y0 = [theta_0, theta_t0, phi_0, phi_t0];
% Solution
f=@(t,y) Pendulum3D(t,y,omega);
[t,y]=ode45(f,[0 Ttot],y0);
% Function
function dy=Pendulum3D(t,y,omega)
dy=[y(2);(sin(y(1))*cos(y(1))*(y(4))^2)-omega*sin(y(1)); y(4); (-2*y(4)*y(2)*cot(y(1)))];
  1 Comment
Bjorn Gustavsson
Bjorn Gustavsson on 1 Feb 2021
Check what happens when cot(theta) goes to infinity, that is the first worrisome point in your code.

Sign in to comment.

Accepted Answer

Jon on 1 Feb 2021
As Bjorn has suggested, you must guard against values of theta where cot(theta) goes to +/- infinity, e.g. 0,pi
Your code seems to run ok for the initial conditions I've edited in below (I commented out the prompts for user input and just supplied values so the results are reproducible)
% Definition of Parameters
g=9.81; % m/s2
l= 1; %input('Strings length: ');
Ttot=10;% input('Total Simulation Time (sec): ');
% Initial Conditions
theta_0 = pi/2; %input('Theta_0 (in form of n*pi): ');
theta_t0 = 0; % input('Theta_t0: ');
phi_0 = pi/4; %input('Phi_0 (in form of n*pi): ');
phi_t0 = 1; %input('Phi_t0: ');
y0 = [theta_0, theta_t0, phi_0, phi_t0];
% Solution
f=@(t,y) Pendulum3D(t,y,omega);
[t,y]=ode45(f,[0 Ttot],y0);
% plot results
I would suggest making your equations more obvious as follows, but it seems that yours are equivalent, just hard to read
function ydot = Pendulum3D(~,y,omega)
% use actual variable names to make code more understandable, help avoid
% errors in formulas
theta = y(1);
thetaDot = y(2);
phi = y(3);
phiDot = y(4);
ydot(1) = thetaDot;
ydot(2) = sin(theta)*cos(theta)*phiDot^2 - omega*sin(theta);
ydot(3) = y(4);
ydot(4) = -2*phiDot*thetaDot*cot(theta);
% make sure it returns as a column
ydot = ydot(:);

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by