Error using movmax index

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david crowley
david crowley el 21 de Feb. de 2021
Comentada: Walter Roberson el 10 de Jun. de 2021
I need to find the number of periods since a stock price recorded an 14-day high. My proposed method was to use the following andpossibly subtract the index from the current row:
n = 14
[M,I] = movmax(high,[n-1 0],'omitnan');
However, I return - "error using movmax. Too many output arguments."
Can someone please assist in my methodology.

Respuestas (1)

Walter Roberson
Walter Roberson el 21 de Feb. de 2021
There is no syntax for movmax() in which it returns a second output. It does not return the indices of the local maxima.
  4 comentarios
Raphael Willi
Raphael Willi el 10 de Jun. de 2021
Loop how?
Walter Roberson
Walter Roberson el 10 de Jun. de 2021
wid = 5;
N = 50;
signal = randi([-9, 9], 1, N)
signal = 1×50
-4 -9 -5 8 -6 -2 7 -3 6 -1 5 6 3 -5 -3 -3 -8 0 -8 7 -9 -3 6 0 4 2 -8 -9 3 -3
for K = 1 : N - wid + 1
[M(K), relI] = max(signal(K:K+wid-1));
I(K) = K + relI - 1;
end
M
M = 1×46
8 8 8 8 7 7 7 6 6 6 6 6 3 0 0 7 7 7 7 7 6 6 6 4 4 3 3 3 3 1
I
I = 1×46
4 4 4 4 7 7 7 9 9 12 12 12 13 18 18 20 20 20 20 20 23 23 23 25 25 29 29 29 29 34

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