check for a pair in power hand
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Jason Earls
el 23 de Mzo. de 2021
i am trying to check for a pair, I need to compare each value in an array to each other in the array.
the difference will be a multuple of 13. exampe 1 and 14 would be a pair.
if mod (card[ct1]-card[ct2],13) ==0; but not sure how to write it. any help appreciated.
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Rik
el 23 de Mzo. de 2021
The feasibility of this depends on the size of the arrays involved. If your vectors are too large, the implicit expansion will cause problems.
v1=randi(26,8,1);
v2=randi(26,8,1);
[ind1,ind2]=find(mod(v1-v2.',13)==0);
pairs=[v1(ind1),v2(ind2)]
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Jan
el 23 de Mzo. de 2021
Editada: Jan
el 23 de Mzo. de 2021
The trivial approach would be two nested loops:
card = randi(20, 1, 1000);
result = zeros(2, numel(card)); % Pre-allocate to maximum size
c = 0;
for i1 = 1:numel(card)
for i2 = 1:numel(card)
if mod(card(i1) - card(i2), 13) == 0
c = c + 1;
result(1, c) = i1;
result(2, c) = i2;
end
end
end
result = result(:, 1:c); % Crop unused elements
Rik's vectorized apporach is smarter.
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