How can I pick out two values of cell array with NaN without using a forloop and using indexing instead?

Hi there. I have a cell with these properties:

 whos all
  Name           Size               Bytes  Class    Attributes

all       226051x1             32616672  cell

>> all{1,1}

ans =

    60    48    62    32

I want the second and third element, such as all{1,1}(1,2:3)=[48 62]

So far I have done it in a forloop, like so:

Flag_DO=NDBCdata.F_DO_mgl;
rawDO=NDBCdata.DO_mgl;
fh1 =@(x)any(isnan(x(:)));
whereNaN_Flag_DO=cellfun(fh1, Flag_DO); 
whereNaN_DO=cellfun(fh1, raw_DO);

mat1=cell2mat(whereNaN_Flag_DO);
mat2=cell2mat(whereNaN_DO);
itrs=size(Flag_DO);
itrs=max(itrs);
Store1=zeros(itrs,2);
ErrNum=cellfun(@double, Flag_DO, 'UniformOutput', false);

for gg=1:itrs
    if mat1(gg) ==0 | mat2(gg) ==0
        Num=ErrNum{gg,1}(1,2:3);
        Store1(gg,:)=Num;
    end
end
meaning=char(Store1);

I also noticed that the if statement isn't being used because the output is the same number of elements as the input, and there is definitely NaN's in the input.

Answer 1

[Matthew Eicholtz]

If I understand you correctly, the following code should work:

a = {1:4;[5 nan 6 nan];[8 9 nan 10];[11 nan nan 12];13:16}; % arbitrary data
b = cell2mat(cellfun(@(c) c(2:3),a,'uni',0)); % resulting matrix

In this case, the variable a is what you are calling all (I don't suggest using variable names that are also built-in MATLAB functions), and b is what you are calling Store1.