Equal Sized random assortment, using randi?
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I have used the following code to generate a matrix of random integers (1's and 2's). However, I am finding myself with an unequal amount of random integers in each column (e.g., eleven "1's" and eight "2's" in some columns). I would like to know how I could get a fixed amount of equally sized conditions using this function. In where, I could get ten "1's" and ten "2's" equally spread among all six columns, that still maintains a random order. Am I using the right function (randi) to do accomplish this? Please let me know if I am unclear with my question.
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Image Analyst on 2 May 2021
Chris: first you need to create a column vector with the desired number of 1s and 2s in the column. Then you need to use randperm() to scramble the order and stick it in your output array:
num1s = 10; % Whatever you want
num2s = 10; % Whatever you want
% Make a column vector with the specified number of 1s and 2s in it.
unscrambled = [ones(num1s, 1); 2 * ones(num2s, 1)]
rows = length(unscrambled);
columns = 16; % Whatever you want
output = zeros(rows, columns);
% Scramble and place into the output matrix.
for col = 1 : columns
sortOrder = randperm(rows);
output(:, col) = unscrambled(sortOrder);
output % See it in the command window.
More Answers (1)
Chad Greene on 2 May 2021
Edited: Chad Greene on 2 May 2021
This would be one way to define how many ones and how many twos in each column before randomizing them:
N_cols = 8; % number of columns
N_ones = 10; % number of ones in each column
N_twos = 10; % number of twos in each column
M = [ones(N_ones,N_cols);2*ones(N_twos,N_cols)];
% Shuffle the order of each column:
for k = 1:N_cols
M(:,k) = M(randperm(N_ones+N_twos),k);