How to replace all zeros in a matrix with a vector from 1 to 9 in the order of ascending indices?
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Hearthy Tampol
el 13 de Mayo de 2021
Comentada: Image Analyst
el 14 de Mayo de 2021
I have a matrix x
x =
0 4 9 9 -4 0
4 0 -3 -3 -1 0
0 0 9 9 3 -2
0 0 5 5 10 0
-3 9 -4 -4 10 9
0 0 -1 8 5 0
How can I replace all zeros with values 1 to 9 in the order of ascending indices?
4 comentarios
Image Analyst
el 13 de Mayo de 2021
So why didn't my answer below work for you? It does it columnwise. Please show what you need as the output so I can adjust my code below. Also, is this homework?
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Image Analyst
el 13 de Mayo de 2021
Try this. The replacements are in "column-major" order, since that's how MATLAB does things.
x = [
0 4 9 9 -4 0
4 0 -3 -3 -1 0
0 0 9 9 3 -2
0 0 5 5 10 0
-3 9 -4 -4 10 9
0 0 -1 8 5 0]
zeroMap = x == 0
numZeros = sum(zeroMap(:))
x(zeroMap) = 1 : numZeros
----------------------------------------------------------------------------------
x =
0 4 9 9 -4 0
4 0 -3 -3 -1 0
0 0 9 9 3 -2
0 0 5 5 10 0
-3 9 -4 -4 10 9
0 0 -1 8 5 0
zeroMap =
6×6 logical array
1 0 0 0 0 1
0 1 0 0 0 1
1 1 0 0 0 0
1 1 0 0 0 1
0 0 0 0 0 0
1 1 0 0 0 1
numZeros =
12
x =
1 4 9 9 -4 9
4 5 -3 -3 -1 10
2 6 9 9 3 -2
3 7 5 5 10 11
-3 9 -4 -4 10 9
4 8 -1 8 5 12
If, instead of 1-12, you want to go from 1-9 and then from 1-3, you can do this:
x = [
0 4 9 9 -4 0
4 0 -3 -3 -1 0
0 0 9 9 3 -2
0 0 5 5 10 0
-3 9 -4 -4 10 9
0 0 -1 8 5 0]
zeroMap = x == 0
numZeros = sum(zeroMap(:))
v = rem(0 : numZeros-1, 9) + 1
x(zeroMap) = v
v =
1 2 3 4 5 6 7 8 9 1 2 3
x =
1 4 9 9 -4 9
4 5 -3 -3 -1 1
2 6 9 9 3 -2
3 7 5 5 10 2
-3 9 -4 -4 10 9
4 8 -1 8 5 3
4 comentarios
Image Analyst
el 14 de Mayo de 2021
You're welcome. (Thanks for Accepting the answer to award reputation points.)
Tip: Did you know that you can click the double-page icon in the upper right corner of code sections to copy the code into the clipboard, then you can paste it into MATLAB editor window from the clipboard.
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