How can I divide a matrix in to vectors?

C = [0 0 0 0 1; 1 0 0 0 0; 0 0 0 1 0; 0 0 1 0 0; 0 1 0 0 0;]

need something like this

   c1=[0 0 0 0 1]
   c2=[1 0 0 0 0]

I try to do it like this, but it doesn't work

for j=1:c for i=0:5 vector=1:5; end end

Answer 1

[Matt Fig]

Please read this link before you even think about creating many vectors from an array like this:

It is a bad habit to start, and there are better ways!

Answer 2

[phani]

hi ami try this c1=C(1,:); c2=C(2,:);

i hope it will work.

Answer 3

[Andrei Bobrov]

variant 1

Ccell = mat2cell(C,ones(size(C,1),1),size(C,2));
[C1,C2,C3,C4,C5] = Ccell{:};

variant 2

for jj = 1:size(C,1)
   js = num2str(jj);
   eval(['C', js , '= C(',js,',:)'] );
end

[Jan]

I really think, that the first line "Ccell = mat2cell(C,ones(size(C,1),1),size(C,2))" is enough already. Then the searched variables are Ccell{1}, Ccell{2}, etc. This would be more efficient than creating C1, C2, ... dynamically.

Although your answer matches the question exactly, I'm prefering Matt's "there are better ways" answer.