I think it only takes 5 weighings when N=128. Am I incorrect?
agree 5 weighing for N=128 (worst case scenario you reduce to 43 15 5 2 1 after each consecutive weighing)
the last test case provided by the author is wrong: should be 5 since log(128)/log(3) < 5.
The problem is that the author do not specify an strategy. And as mentioned, dividing by 3 yields a better strategy than 6 weightings for 128. But, my guess is that the author counted the number of divisions instead of the number of weightings 128->[42 42 43] -> [14 14 14; 14 14 15]->[5 5 4; 5 5 5]->[2 2 0; 2 2 1]->[1;2]->1.
Correct the test suite
Flip the main diagonal of a matrix
Make a run-length companion vector
Generate N equally spaced intervals between -L and L
Say something funny
Create matrix of replicated elements
Find out missing number from a vector of 9 elements
Find the solution of algebraic equation
Generate pi using logarithm
Accessing elements on the diagonal
Reverse the elements of an array
Find the treasures in MATLAB Central and discover how the community can help you!
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office