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Problem 45964. Compute the nth Pythagorean prime

Solution 3036010

Submitted on 2 Oct 2020 by James
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Test Suite

Test Status Code Input and Output
1   Pass
n = 1; pp_correct = 5; [pp1,a1,b1] = PythagoreanPrime(n); assert(isequal(pp1,pp_correct)) assert(a1 == floor(a1) && b1 == floor(b1) && a1^2+b1^2 == pp1)

2   Pass
n = 5; pp_correct = 37; [pp1,a1,b1] = PythagoreanPrime(n); assert(isequal(pp1,pp_correct)) assert(a1 == floor(a1) && b1 == floor(b1) && a1^2+b1^2 == pp1)

3   Pass
n = 25; pp_correct = 257; [pp1,a1,b1] = PythagoreanPrime(n); assert(isequal(pp1,pp_correct)) assert(a1 == floor(a1) && b1 == floor(b1) && a1^2+b1^2 == pp1)

4   Pass
n = 125; pp_correct = 1657; [pp1,a1,b1] = PythagoreanPrime(n); assert(isequal(pp1,pp_correct)) assert(a1 == floor(a1) && b1 == floor(b1) && a1^2+b1^2 == pp1)

5   Pass
n = 625; pp_correct = 10313; [pp1,a1,b1] = PythagoreanPrime(n); assert(isequal(pp1,pp_correct)) assert(a1 == floor(a1) && b1 == floor(b1) && a1^2+b1^2 == pp1)

6   Pass
n = 3125; pp_correct = 62497; [pp1,a1,b1] = PythagoreanPrime(n); assert(isequal(pp1,pp_correct)) assert(a1 == floor(a1) && b1 == floor(b1) && a1^2+b1^2 == pp1)

7   Pass
n = 15625; pp_correct = 367229; [pp1,a1,b1] = PythagoreanPrime(n); assert(isequal(pp1,pp_correct)) assert(a1 == floor(a1) && b1 == floor(b1) && a1^2+b1^2 == pp1)

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