Problem 46716. Matrix with increasing numbers (★★★★)

Created by Anirban Pal

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Create a matrix Z with m rows and n columns that contain the numbers 1 to m*n in ascending order in the following manner. The first row will contain numbers 1 to n. The second row will contain n+1 to 2n and so on. Thus, if m = 3, n = 4, the output matrix Z will have 3 rows and 4 columns and will be the following:
[1 2 3 4;
5 6 7 8;
9 10 11 12]
This become trivial if you use loops, but do this without using loops, i.e. for/while not permitted. Additionally, the reshape command makes this very easy, so avoid that as well.

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Last Solution submitted on Jul 16, 2024

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Christian Schröder on 27 Oct 2022

Your test suite detecting for loops is overzealous and trips up on arrayfun(..., "UniformOutput", false).

goc3 on 15 Apr 2023

Fortunately, there is an abbreviation that can be used that will not be triggered by searches for "for": arrayfun(..., "Uni", 0). Incidentally, "Un" (or "un") can also be used while 0 is equivalent to false in this context. These abbreviations also work for cellfun.

Dyuman Joshi on 15 Apr 2023

Technically, arrayfun (cellfun as well) is just a loop in disguise. All in all, OP is asking for a vectorized solution.

Christian Schröder on 16 Apr 2023

@Dyuman You're right of course, but technically the problem description also says "do this without using loops, i.e. for/while not permitted", so arrayfun, cellfun and all the other kinds of fun that you can have with MATLAB are permitted. :)

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Problem 46716. Matrix with increasing numbers (★★★★)

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Problem 46716. Matrix with increasing numbers (★★★★)

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Last 200 Solutions

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