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Anand P


Last seen: casi 4 años hace Con actividad desde 2019

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Fitting a quadratic model with the coefficient of linear term fixed
A quadratic equation is given by y = ax^2 + b^x +c. Matlab function 'fit' is used to fit a relation between input and output....

alrededor de 4 años hace | 1 respuesta | 0

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Stacking indexed images and view the resulting volume
I have used the following code to convert RGB images to indexed image and stack them as a cube A =imread('image2.png'); %A is a...

casi 5 años hace | 1 respuesta | 0

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Volume level equivalent of imagesc
Imagesc can be used to view images. Is there any equivalent command in the volume domain which does the same function to a volu...

casi 5 años hace | 1 respuesta | 0

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Viewing a volumetric data using user defined colormap
Initially I have converted an RGB image, represented by a 3 dimensional matrix into an indexed image represented by a 2 dimensio...

casi 5 años hace | 1 respuesta | 0

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Viewing and saving hyperspectral images
The matrix representation of a hyperspectral image is m*n*k. How do I view this hyperspectral image in MATLAB ? How do I save t...

casi 5 años hace | 0 respuestas | 0

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Image dimension for Hyperspectral data cube
As far as I have understood, hyperspectral cube consists of various images stacked one over the other. The dimensions of each of...

casi 5 años hace | 0 respuestas | 0

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MATRIX REPRESENTATION OF COLOUR IMAGES
Why are some colour imges represented by 2 dimensional matrix while other colour images are represented by 3 dimensional matrix ...

casi 5 años hace | 3 respuestas | 0

3

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Stacking multiple RGB images and viewing it in a volumetric manner
Can someone provide me with the code to stack multiple RGB images one over the other and to view the created stack in a volumetr...

casi 5 años hace | 0 respuestas | 0

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Stacking 2D images to form 3D stack and viewing it in a volumetric manner
I want to stack four 2D images (so that the stack becomes 3D) and view the 3D stack. Can someone provide me with the correspondi...

casi 5 años hace | 1 respuesta | 0

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