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Integrating the density function of Brownian motion
Maybe it helps to resolve the integration with respect to t: syms t T real positive syms x real g = 1/sqrt(t)*exp(-x^2/t); i...

más de 2 años hace | 0

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Helmholtz problem in circular disk
According to your code, data(i,j) is a zero of besselj(j-1,x) in the interval [(i-1)*pi i*pi]. So let's plot besselj(1,x) and b...

más de 2 años hace | 1

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How to build a graph using stem for a given equation?
Since your delta function does not support array inputs, you must use something like x1=a1*arrayfun(@(n1)delta(n1-b1),n1) inst...

más de 2 años hace | 1

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How do I code a Hamiltonian Cycle in an undirected weighted graph?
I didn't test it yet, but maybe this one from the File Exchange: https://uk.mathworks.com/matlabcentral/fileexchange/51610-hami...

más de 2 años hace | 0

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Find critical points of parametric function
The critical points are solutions of a polynomial of degree 6 in z. There is no solution formula for roots of polynomials of deg...

más de 2 años hace | 1

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Central and Forward difference schemes heat conduction for two-layer materials
heattransfer() function heattransfer xstart = 0; xend = 1; xinterface = 0.25; xmesh1 = linspace(xstart,xinterface,25); xme...

más de 2 años hace | 0

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Average Optimization using GA or intlinprog algorithms
https://uk.mathworks.com/matlabcentral/answers/2063957-optimization-problem-with-array-input?s_tid=srchtitle

más de 2 años hace | 0

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how to ues the exponentials and derivatives in bvp4c
yp1 = deval(S,1) ym1 = deval(S,-1); T1= exp(-b1*(1+m))*ym1(4); T2= exp(-b1)*yp1(4); N1= -(1+b2*(1+m))*ym1(5); N2= -(1+b2)*y...

más de 2 años hace | 0

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Nonlinear time dependent 2D system of PDE's
I doubt there is a software capable to handle this kind of PDE system automatically. You will have to discretize the spatial d...

más de 2 años hace | 0

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How could I have these two erros when I did everything right (otherwise)?
c_p defined in your script does not mean that it is also visible in your functions. Either define the functions as nested funct...

más de 2 años hace | 0

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Problem with solving two differential equations depending on each other
Since W0 = 0, you get Re = 0 and thus lambda = something undefined (you divide by Re !). What does the c stand for in dm^3/c fo...

más de 2 años hace | 0

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How to plot function with different first x values?
I = @(R)0.5*(R>=0 & R<10)+5/R*(R>=10 & R<=100); U = @(R)0.5*R*(R>=0 & R<10)+5*(R>=10 & R<=100); P = @(R)I(R)*U(R); R = 0:0.1:...

más de 2 años hace | 0

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Why eigen vector looks different than the calculated one
Eigenvectors are only unique up to a multiplicative constant, and MATLAB's eigenvectors are normalized to be of norm 1: [1;-3]/...

más de 2 años hace | 0

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Paramter optimization using fmincon
It seems that the model is not able to reproduce your measurement data. The curves look qualitatively different. clc; clear; ...

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i make a code of shooting method for 3rd order differential equation but i dont get the accurate result
y20 = 2; sol = fsolve(@fun_shooting,y20); [X,Y] = fun_ode(sol); plot(X,Y(:,1)) function res = fun_shooting(y2) [X,Y] = ...

más de 2 años hace | 1

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Non linear system by Newton-Raphson
x1 = 1; y1 = 1; P = [x1 ; y1]; F= @(x,y) [atan(y)-y.*x.^2 ; x.^2+y.^2-2*x]; JF = @(x,y) [-2.*x.*y (1/(1+y.^2))-(x.^(-2)) ;...

más de 2 años hace | 2

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need help getting this to run
Maybe initial_strain_index = find(colum1 == min(colum1),'first'); peak_stress_index = find(colum3 == max(colum3),'first'); in...

más de 2 años hace | 0

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How to visualise the 'output' of a Neumann boundary condition?
I think the example "Heat Transfer Problem on a Square" under https://uk.mathworks.com/help/pde/ug/pde.stationaryresults.eval...

más de 2 años hace | 1

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Can PDE solver pdepe handle discontinous initial conditions?
Depends on the equation(s) you want to solve. If there is much diffusion in your equation(s), usually yes. Else usually no.

más de 2 años hace | 1

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one of the terms "Rho_net" on the RHS of an set is varying with time over the tspan. How do I implement the set of the ODEs such that the term updates at every time step?
If you insert the line size(dYdt(tspans(1),initial_conditions)) before the call to ode45, you will see that your function dYdt...

más de 2 años hace | 0

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Newton Raphson gives answers divided by 0
Your linear systems in the course of the Newton iterations cannot be solved since the Jacobian is rank-deficient (it has only ra...

más de 2 años hace | 1

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I am wanting to delete these entries of vector x when x = 0. How do I do this. Matlab gives me an error right now saying index cannot exceed 38 but I don't know what's wrong.
Use x(x==0) = []; instead of for i = 1:56 if x(i) == 0 x(i) = [] end end The length of the x-vector wil...

más de 2 años hace | 0

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I am trying to create a while loop where a marker can't leave a box of x = -10 and y = 10, y = -10. Once the marker reaches x = 11 I want the loop to stop.
Put the k = k+1 at the end of the while-loop, not at the beginning. And if x(k) == -10, you only set x(k+1), but not y(k+1). Th...

más de 2 años hace | 0

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solving for y in equation
a = 85.147; h = 55; v = 50; u = 25; f = @(x,y)x-sqrt(a^2+h^2)-(h-y).*cot(asin((h-y)/v))+(h-u)*cot(pi/4-asin((h-y)/v))+v*sin(...

más de 2 años hace | 0

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Iteration loop for a function to reach a certain value.
g=9.81; NU=2.52; k=.0293;%from book L=.025;%plate to cover spacing m sigma=5.6697e-8; epsilonp=0.95;%plate emittance epsil...

más de 2 años hace | 0

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Why do I have a never ending loop ?
The initial condition at t = 0 seems to be T = 4 for all x in your code. But you must set boundary conditions for T at x = 0 an...

más de 2 años hace | 0

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Multi objective optimization for genetic algorithm showing out of bound solutions.
If you plot x(:,2) against x(:,1), you will see that both respect the bounds you prescribed: figure(2) [x1,idx] = sort(x(:,1))...

más de 2 años hace | 2

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Please help to solve the error in evaluating a system of odes using ode45
Rho_net is an array of length 365, but it must be a single scalar value in ode_2. If you want to evaluate the array at time t g...

más de 2 años hace | 1

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Solving the differential equation by the Runge-Kutta method (ode45)
[t, y] = ode45(@odefun2,[0 3],[1,0]); plot(t,y(:,1)) function dfdt = odefun2(x,y) w = 2e16; r0 = 30e-6; c = 3e8; ...

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Breaking down a numerical integration into two parts
I1 = dx/2 * f(x0) + dx * sum_{i=1}^{n-1} f(xi) + dx/2 * f(xn) I2 = dx/2 * f(xn) + dx * sum_{i=n+1}^{n+m-1} f(xi) + dx/2 * f...

más de 2 años hace | 1

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