Respondida
How can I put a loop here?
V = [0.5 1 2 3 4 6 10].'; del = 0:1:90; del_r = del.*pi./180; x = V.*tan(del_r); del_r2 = atan(x); del2 = del_r2*180./pi;...

casi 4 años hace | 0

| aceptada

Respondida
WATERMODEL returns a vector of length 825, but the length of initial conditions vector is 3. The vector returned by WATERMODEL and the initial conditions vector must have the
% Load file with variables temperature, ET etc, %% data=readtable("https://de.mathworks.com/matlabcentral/answers/uploaded_fil...

casi 4 años hace | 0

| aceptada

Respondida
can any one tell me why this error has occurred.
i is a vector (at least when the loop index LL is 2, for LL = 1 i is taken as the imaginary unit because it's not yet defined), ...

casi 4 años hace | 0

| aceptada

Respondida
How can I use fzero on these two functions?
Use the original equation. Why do you take log on both sides - it only implies problems for x <= 3/4. f = @(x)4*x-3-exp(-0.1*x)...

casi 4 años hace | 0

Respondida
how do i get the the fifth and fourth number form behind?
x = [2361273621, 2937812378, 2367823827]; b = arrayfun(@(a)num2str(a),x,'uni',0); b = arrayfun(@(i)b{i}(end-4:end-3),1:length(...

casi 4 años hace | 0

Respondida
Plotting using MATLAB problem
https://www.youtube.com/watch?v=GrpDgOjR5ZA

casi 4 años hace | 0

Respondida
How can i put a stopping criterion for this bisection method code in matlab?
f_x= @(x)sin(5*x)+cos(2*x); p_old = 0; % give an initial value to it x_l =2; x_u = 10; x=x_l:0.01:x_u; hold on plot(x,f...

casi 4 años hace | 0

Respondida
Is there any mathematical method of curve fitting for cases when the modeling function is unknown (another degree of freedom for the form of the function)?
No, there is no such method. Often, physical considerations are a way to decide for a suitable model function. If this is not ...

casi 4 años hace | 0

Respondida
How to generate a random number that is either 100, 200, or 300.
Hint: 100*1 = 100 100*2 = 200 100*3 = 300

casi 4 años hace | 0

Respondida
writing the equation of normalize correlation
rng('default') x = 4; y = 5; w = rand(x,y); wstroke = rand(x,y); NC = sum(w.*wstroke,'all')/sum(w.^2,'all')

casi 4 años hace | 0

| aceptada

Respondida
Nonlinear optimization not working
fun = @(x,y,z) 25*x + 37*y + 48*z; x0 = [0,0,0]; A = [0 -1 2]; b = [0]; Aeq = []; beq = []; lb = [200 200 200]; ub = [...

casi 4 años hace | 0

| aceptada

Respondida
Getting NaN greater values in a function
warning('off') iterations = [10, 100, 1000]; count = 1; p = 0.5; for n = iterations figure(); hold on; for ...

casi 4 años hace | 0

| aceptada

Respondida
How to solve 2nd order multiple variable equation with ode45
syms t y1(t) y2(t) syms c2 m1 m2 k1 k2 F eqn1 = diff(y1,t,2) + c2/m1*(diff(y1,t)-diff(y2,t))+k1/m1*y1+k2/m1*(y1-y2)-F == 0; e...

casi 4 años hace | 0

Respondida
The plot of a given equation
h=0:0.01:2; Fmax = 37509.41*sqrt(h); plot(h,Fmax)

casi 4 años hace | 0

| aceptada

Respondida
how to split a 4x3 matrix in half
If the number of columns of arr1 is divisible by 2: arr1 = [1 2 3 4;5 6 7 8;9 10 11 12]; arr1_half = arr1(:,1:size(arr1,2)/2)

casi 4 años hace | 0

Respondida
how to write equation in matlab for E(t-tp) where the E is E(t) but introduce a tp delay time.
You will need to make a change in the unit of time in your equations such that the delay time is in the order of 1 - it's not p...

casi 4 años hace | 1

| aceptada

Respondida
Provide Jacobian matrix to ode15i for solving DAE system
y0 = [1; 0; 0]; yp0 = [0; 0; 0]; options = odeset('RelTol',1e-4,'AbsTol',[1e-6 1e-10 1e-6], 'Jacobian', @Jac_robertsidae); [y...

casi 4 años hace | 1

| aceptada

Respondida
Define a variable on a spline
n = 3; n1 = n-1; a = 20; b = 10; P = [0 b;0 0;a 0]; x = P(:,1); y = P(:,2); T ...

casi 4 años hace | 1

Respondida
bisection method error symbolic
syms y q=20; g=9.8; b=3+y; ac=3*y+y^2/2; f= 1-q^2/(g*ac^3)*b; x1=0.5; xu=2.5; hold on fplot(f,[0.5 2.5]) grid on f =...

casi 4 años hace | 0

| aceptada

Respondida
Bvp4c Unable to solve the collocation equations -- a singular Jacobian Encountered
clc; p = 0.01; Betaf = 207; Betas = 17; Beta = 0.5; kof = 0.613; kos = 400; m = 1; b2 = 0.5; b1 = 0.5; G1 = 5; G2 = 5...

casi 4 años hace | 0

| aceptada

Respondida
Third for loop runs, second and third loops do not
If val_T were 1, only the third loop was entered. But we don't know the value of val_T.

casi 4 años hace | 0

| aceptada

Respondida
Using euler's method to plot x(t) graph
You pass "ICs(z)" and "timeVector" to "eulersub". In the function, they get the names a and b. But a and b are never referenced ...

casi 4 años hace | 0

| aceptada

Respondida
How to solve this without syms x
fun = @(x) x.^2./(1+sqrt(x)) ; sol = fzero(@(x)fun(x)-2,10); x = 0:0.1:4; plot(x,fun(x),sol,fun(sol),'o')

casi 4 años hace | 0

| aceptada

Respondida
My code is outputting very illogical answers for the second block (my second vector loop equation).
% given values R1 = 59.7; R2 = 18.8; R3 = 41.0; R4 = 40.1; R5 = 136.4; R6 = 11.9; R7 = 15.6; R8 = 11.7; Rgi = 13.1; Re...

casi 4 años hace | 0

Respondida
Graph not being displayed
./ instead of simple / : x=linspace(-5,5,130); y=(2*x.^2-2*x-1)./(x.^4+1); plot(x,y);

casi 4 años hace | 0

| aceptada

Respondida
Euler Integration Step Size Change
Only integer values can be used for array indexing. The loop must run from i=1 to i=5000 instead.

casi 4 años hace | 0

| aceptada

Respondida
How can i plot dy/dx function?
xspan = (30:0.1:900); y0 = 0; options = odeset('RelTol',1e-12,'AbsTol',1e-12); [x,y] = ode15s(@(x,y) odefun(x,y), xspan, y0, ...

casi 4 años hace | 0

Respondida
What is wrong with the function code when it can work perfectly without function code
Works for me. [k,p,err,P] = fixpt(@(x) sin(x)-1,-1,0.00001,100) function [k,p,err,P] = fixpt(g,po,tol,maxi) % g is the functi...

casi 4 años hace | 0

| aceptada

Respondida
Error tolerance in matlab
The ode integrators try to guarantee a predefined error tolerance when solving your system of ordinary differential equations. I...

casi 4 años hace | 0

Respondida
How do I go by this in Matlab?
%************ Variable declaration****************** rng('default') t = -20:0.1:20; n = 1000; % number of realizations signa...

casi 4 años hace | 0

| aceptada