How to extract data from a cell in a specific way ?

Suppose I have the following code
for n = 1:21
sz = [23,42000];
data = cell(sz);
for k = 1:12
x=foo( );
data{k}=x;
end
end
after its being executed I get a cell named data which has 12 1x69 arrays like this
1x69 double
1x69 double
1x69 double
1x69 double
1x69 double
1x69 double
1x69 double
1x69 double
1x69 double
1x69 double
1x69 double
1x69 double
Now I want to save this in an array outside of inside for and also add to this array the following 12 1x69 arrays for the end 20 itterations of the outside loop.
Eventually, I want to have 12x21=252 1x69 arrays in a single array 252x69.
I hope you guys understood what I am asking and I wish someone out there help me here, because I am clueless here...

2 comentarios

sixwwwwww
sixwwwwww el 29 de Oct. de 2013
What is 'y' here?
Ignore y , I'm removing it. Suppose foo is just providing values for cell

Iniciar sesión para comentar.

 Respuesta aceptada

sixwwwwww
sixwwwwww el 29 de Oct. de 2013
Dear Stamatis, here is code for converting cell array into a matrix:
for i = 1:12
data{i} = rand(1, 69); % create cell having 12 arrays of 1x69
end
a = reshape(cell2mat(data), [], 69); % storing the arrays in a matrix
Is it what you need?

4 comentarios

Sorry but this is not what I am looking for. For every itteration of outside for , inside for will place those values as I described above in cell {data} and I am looking for a way to extract those values for every itteration of outside for in a seperate array for later use.
you can do it like this(if I understood correctly):
for n = 1:21
data1{n} = data; % data1 is a big cell array and its each cell has 12 1x69 arrays
sz = [23,42000];
data = cell(sz);
for k = 1:12
x=foo( );
data{k}=x;
end
end
Is it ok now?
it does something interesting, I think its close to what I am looking for, I am going to work it out a bit and hopefully get the desired results. Thanks !
sixwwwwww
sixwwwwww el 30 de Oct. de 2013
You are welcome

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Preguntada:

el 29 de Oct. de 2013

Comentada:

el 30 de Oct. de 2013

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by