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I'm trying to make a Simulink model consisting of a clock (as a source) and a MATLAB function that calculates the following:
Y=exp(t) * sigma(n=1:inf)[n * exp(n*t)]
Can anybody help me write the code?
Respuestas (5)
Paulo Silva
el 29 de Jun. de 2011
MATLAB Fcn
exp(u)*sum([1:10].* exp([1:10].*u)) %not infinite sum but close enough
C.J. Harris
el 29 de Jun. de 2011
0 votos
You won't be able to write an infinite series directly. You will either have to use an approximation, or only calculate the sum for the first 'n' elements.
Walter Roberson
el 29 de Jun. de 2011
If and only if t is less than 0,
Y = exp(2*t)/(exp(t)-1)^2
That is, sum(n*exp(n*t), n = 1 .. infinity) is exp(t)/(exp(t)-1)^2
If t is 0 or greater, the sum is infinite, as you are adding together numbers that increase infinitely.
Hossein sadri
el 30 de Jun. de 2011
0 votos
2 comentarios
Paulo Silva
el 30 de Jun. de 2011
[1:10].^2
Walter Roberson
el 30 de Jun. de 2011
n.^2 instead of n^2
But n^2*exp(u) has the same problem I described above of having an infinite value unless u is negative.
amey
el 1 de Jul. de 2011
0 votos
n=1:1:100; y=exp(0.4)*(n.*exp(0.4*n)); tot=0; for i=1:100; tot=tot+y(i); end disp(tot);
2 comentarios
amey
el 1 de Jul. de 2011
u = 0.4 ; % assumed
n=1:1:100; % only first 100 terms taken
Paulo Silva
el 1 de Jul. de 2011
is there another question for us?
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