how do you write a conditional struct?

 Respuesta aceptada

Walter Roberson
Walter Roberson el 18 de Nov. de 2013
At the beginning start with
data = [];
Then, in each of the error cases, after you disp() the string, add
return
before the "end" of the "if"
if condition
disp('message')
return
end

Más respuestas (1)

Azzi Abdelmalek
Azzi Abdelmalek el 18 de Nov. de 2013

0 votos

Maybe you are asking about if/elseif/else

4 comentarios

vishant m.
vishant m. el 18 de Nov. de 2013
i tried using if, but it doesnt work :( can you give a simple example
Matt J
Matt J el 18 de Nov. de 2013
Editada: Matt J el 18 de Nov. de 2013
@vishant
Why don't you give an example of what doesn't work and describe what you want to happen instead.
vishant m.
vishant m. el 18 de Nov. de 2013
Editada: Azzi Abdelmalek el 18 de Nov. de 2013
function data=test3(n)
if isnumeric(n)==0;
n=([1 2 3 4]); display('input has two many terms or is not a vector');
end
if isvector(n)==0;
n=([1 2 3 4]); display('input has two many terms or is not a vectorl');
end
x=linspace(-5,5,1000);
y=polyval(n,x);
plot(x,y);
q=roots(n);
data=plot(q(imag(q)==0), zeros(sum(imag(q)==0)),'r+');
data= struct('x',x,'p',n,'rp',q,'rpp',q(imag(q)==0),'px',(x));
end
this is the code, you can see the struct. there are 2 if functions at the start, i need the struct to give ans[] when the condition of any of the ifs applies.
Azzi Abdelmalek
Azzi Abdelmalek el 18 de Nov. de 2013
[i need the struct to give ans[] when the condition of any of the ifs applies.] I can't understand what you mean

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