How to display the result of a cycle in a single matrix of a certain size

Hello, I have a cycle:

l=[];
m=[1 0 2 3 5 7 1; 1 0 2 3 5 7 1]
for k=1:2
    r=m(k,1:7);
    for j=r
      if j==0
         z = zeros(1,8,'int8');
         z(1)=1;
         l=[l; z];
      else
         z = zeros(1,8,'int8');
         z(j+1)=j;
         l=[l; z];
      end
     end
   end

Input - a 2 strings, so as to make the output results have dimension 2x7*8 = 2x56???

In current code the results output as matrix 14x8

[Walter Roberson]

Why are you setting all of z to 0 each time?

Which variable are you hoping will become 2 x 56 ?

[Meffix]

To represent each symbol, such 1 as a 0 1 0 0 0 0 0 0.

When the input data - string, each symbol of m is displayed as above specified sequence. That is a sequence of 1 х 8 * 7 =1 х 56.

I would like to dimension a variable l had 2x56.

[Image Analyst]

Clear as mud.

Answer 1

[Amit]

I think you are looking for something like this:

m=[1 0 2 3 5 7 1; 1 0 2 3 5 7 1];
lnew = zeros(2,56,'int8');
for k=1:2
    l=[];
    r=m(k,1:7);
    for j=r
        if j==0
            z = zeros(8,1,'int8');
            z(1)=1;
            l=[l; z];
        else
            z = zeros(8,1,'int8');
            z(j+1)=j;
            l=[l; z];
        end
    end
    lnew(k,:) = l;
end

note: lnew is the matrix with size 2x56

[Meffix]

Thank you very much!