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error with results, matlab

3 visualizaciones (últimos 30 días)
Monika
Monika el 21 de En. de 2014
Comentada: Monika el 22 de En. de 2014
Where is error? My program showed my only WYKRYTO, but I don't know what.
fprintf('\nWYKRYTO: ');
if (kaszel == max([kaszel, smiech, krzyk, chrzakanie]))
fprintf('kaszel');
elseif (smiech == max([kaszel, smiech, krzyk, chrzakanie]))
fprintf('smiech');
elseif (krzyk == max([kaszel, smiech, krzyk, chrzakanie]))
fprintf('krzyk');
elseif (chrzakanie == max([kaszel, smiech, krzyk, chrzakanie]))
fprintf('chrzakanie');
end
  13 comentarios
Monika
Monika el 21 de En. de 2014
Editada: Walter Roberson el 21 de En. de 2014
Size of my signal is depends on which signal will be my input. I have 64 signals. I can make 64 different inputs.
>> disp(class(kaszel))
double
>> size(kaszel)
ans =
107 13
>> size(smiech)
ans =
107 13
>> size(krzyk)
ans =
107 13
>> , size(chrzakanie)
ans =
107 13
Monika
Monika el 21 de En. de 2014
Editada: Walter Roberson el 22 de En. de 2014
My teacher told me, that I can the above code I can write in two lines.
[junk classID(i)] = max([sum(kaszel)
acc = sum(classID==labels)/length(labels)
But I don't know, how I should use acc

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Respuesta aceptada

Walter Roberson
Walter Roberson el 21 de En. de 2014
max([array1, array2])
means
max(horzcat(array1, array2))
which in turn means
max(horzcat(array1, array2), [], 1)
which will calculate the column-by-column maximum of horzcat(array1, array2), which is going to give you a result which is 1 x (size(array1,2) + size(array2,2)) .
And then you try to compare the entire array array1 to the result of the max(), so you are comparing
size(array1,1) x size(array1,2)
to
1 x (size(array1,2) + size(array2,2))
and you can see by examination that the only way that can work is if array1 only has a single row and array2 is empty. (Well, that case would be treated differently by MATLAB, but you would still end up with mismatched lengths for the comparison)
Taking into account that you have entire arrays to be compared, what do you want your output to be? A 2D cell array of strings that indicates at each location which of the four arrays was the maximum at that point ? Or do you wish to know which of the four has the greatest average magnitude? Or something else?
  9 comentarios
Walter Roberson
Walter Roberson el 22 de En. de 2014
Please show your current code fragment.
Monika
Monika el 22 de En. de 2014
fprintf('\nObliczone wartości prawdopodobieństwa przynależenia do poszczególnych klas:\n');
fprintf('Kaszel: %d\nŚmiech: %d\nKrzyk: %d\nChrząkanie: %d\n',kaszel,smiech,krzyk,chrzakanie);
fprintf('\nProbka: %s',pliki(numer_pliku).klasa);
wavplay(sygnal,Fs);
fprintf('\nWYKRYTO: ');
T = cat(3, kaszel, smiech, krzyk, chrzakanie);
[maxval, IDs] = max(T, [], 3);
accumarray(IDs(:), 1)
fprintf('\n======================================================================');
end
fprintf('Zakończono działania skryptu\n');
else
fprintf('Niewystarczająca liczba próbek aby wyznaczyć GMM!');
fprintf('\nNaciśnij dowolny klawisz, aby kontynuować...');
pause;
rozpoznawanie_dzwiekow;
end

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Más respuestas (2)

Azzi Abdelmalek
Azzi Abdelmalek el 21 de En. de 2014
Maybe you want
fprintf('\\nWYKRYTO: ');
  3 comentarios
Azzi Abdelmalek
Azzi Abdelmalek el 21 de En. de 2014
If you give some data we can test your code.
Monika
Monika el 21 de En. de 2014
Editada: Walter Roberson el 21 de En. de 2014

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per isakson
per isakson el 21 de En. de 2014
  2 comentarios
Matt J
Matt J el 21 de En. de 2014
Hard to imagine that applies to max() operations. I'm not encountering issues, at least.
per isakson
per isakson el 22 de En. de 2014
Editada: per isakson el 22 de En. de 2014
Agree, but it's a good habit not to use "==" with floats.

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