Loss of interp1 functionality
Mostrar comentarios más antiguos
pp = interp1(x,v,'linear','pp');
is being removed. Seems like a withdrawal of capabilities to me. What about people who want the pp form to analyze breaks and coefficients, etc... ?
Am I missing something? Is there supposed to be a new and improved way to get the pp form?
1 comentario
Matt J
el 31 de En. de 2014
Respuestas (0)
Categorías
Más información sobre Polynomials en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!