function chebyshev (a, b, numpolys)
t=a:0.1:b;
allp=zeros(numpolys, length(t));
for n=1:numploys
x=(a+b)/2+(b-a)/2*cos((2*(1:n)-1)*pi/(2*n));
y=(1)./(x.^2+1);
allp(n,:)=newton(x, y, t);
end
plot (t, allp)
end
function p=newton(x,y,t)
n=length(x);
x=30;
y=1.0803306e-44;
t=[a,b];
c=y;
for k=2:n
c(k:n)=(c(k:n)-c(k-1))./(x(k:n)-x(k-1));
end
p=c(n)*ones(size(t));
for k=n-1:-1:1
p=p.*(t-x(k))+c(k);
end
end

 Respuesta aceptada

Wayne King
Wayne King el 6 de Feb. de 2014
Editada: Wayne King el 6 de Feb. de 2014

0 votos

The simple answer is your input argument is spelled numpolys in the function declaration, but you spell it numploys in the for loop.
But you have other problems, for example you have a,b internal to the subfunction newton(), but you don't pass those.

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