need you help please please

>> A=[1 2;3 4]; >> B=[9 8 7;6 5 4;3 2 1]; >> a=[11,12] >> b=[21;22]; >> c=[19 18 17]; >> d=[29;28;27];
i am stuck on these questions , i did the rest but really stuck on these question , i spend almost 4 hours playing around with different ways, but can't get the right answer. any help will be much appreciated. Thank you soo much

Respuestas (2)

Mischa Kim
Mischa Kim el 23 de Feb. de 2014
Editada: Mischa Kim el 23 de Feb. de 2014

0 votos

John, for the first one, use
ans1 = [a b'; d B]
it's simply putting together vectors and matrices in the correct order. To get the 1's in the second example, you could use A(1,1), four times. And so on and so forth...

6 comentarios

john hollywood
john hollywood el 23 de Feb. de 2014
thank you soo much it works , what about part F and G '
Mischa Kim
Mischa Kim el 23 de Feb. de 2014
F works just the same: put together vectors in the correct order. With the prime (') you can turn a column into a row vector, and vice versa.
G: I already showed you how to get 1's. The zero matrix (2-by-2) you get by using A-A .
john hollywood
john hollywood el 24 de Feb. de 2014
Editada: john hollywood el 24 de Feb. de 2014
for 'part F' i just don't how put number "29" in there. also for 'Part G', i just don't know how to put matrix A in that diagonal form.i did try switch rows and columns and also tried transpos but nothing seems to work. i used diag(diag(A')) But its not working. Thank you soo much
Mischa Kim
Mischa Kim el 24 de Feb. de 2014
Editada: Mischa Kim el 24 de Feb. de 2014
Here you go:
F = [[A(1,1) A(1,1); A(1,1) A(1,1)] a' b; c d(1)]
G = [A(1,1) A(1,1)-A(1,1) A(1,1) A(1,1)-A(1,1);
A(1,1)-A(1,1) 2*A(1,1) A(1,1)-A(1,1) A(1,1);
[A(1,1) A(1,1); A(1,1) A(1,1)] A-A]
Please post follow-up question and comments as comment, not answers.
Walter Roberson
Walter Roberson el 24 de Feb. de 2014
The "2*" of "2*A(1,1)" violates the constraint of not introducing any new scalars. You could replace the "2*A(1,1)" with A(1,1)+A(1,1)
However, as I read the question, the indices (1,1) would be introduced scalars. Forming the 2 x 2 sub-block of 1's then becomes difficult.
Sagar Damle
Sagar Damle el 25 de Feb. de 2014
I think we are allowed to use scalars as indices but not as extra data.
John,where did you get these questions(from which book)?If they are in a book,are they in 'Exercise' of a chapter?What are the contents of that chapter?(This will help us to narrow our thinking,because exercise of a chapter contains problems related to that chapter.)
Can we use rem(input_matrix,2) to get output in terms of 0's and 1's only?

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john hollywood
john hollywood el 24 de Feb. de 2014

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for 'part F' i just don't how put number "29" in there. also for 'Part G', i just don't know how to put matrix A in that diagonal form.i did try switch rows and columns and also tried transpos but nothing seems to work. i used diag(diag(A')) But its not working. Thank you soo much

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