Problem Integrating sin(2*x)
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Ricardo
el 5 de Mzo. de 2014
Comentada: Gustavo Leal
el 9 de Oct. de 2017
>> syms x >> f=sin(2*x)
f =
sin(2*x)
>> int(f)
ans =
sin(x)^2
>>
I am sure it is wrong because it should be -1/2+sin(x)^2
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Paul
el 5 de Mzo. de 2014
The integral is:
sin(x)^2 + C
but Matlab just doesn't show the constant. How do you get the -1/2? Because if you differentiate the integral (sin(x)^2 + C) you get:
2*sin(x)*cos(x) = sin(2*x)
And the constant differentiated gives 0 since it doesnt depend on x.
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Gustavo Leal
el 9 de Oct. de 2017
sin(pi)^2 != -cos (2pi)/2 ,for example, something its wrong with this function at MATLab
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