solving linear equations in a loop
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Krzysztof
el 21 de Mzo. de 2014
The documentation for inv says:
A frequent misuse of inv arises when solving the system of linear equations Ax = b. One way to solve this is with x = inv(A)*b. A better way, from both an execution time and numerical accuracy standpoint, is to use the matrix division operator x = A\b.
The above taken for granted, is it nevertheless reasonable to precalculate invA = inv(A) in front of a loop containing (A\Xi), especially one that necessarily sequential?
0 comentarios
Respuesta aceptada
Matt J
el 21 de Mzo. de 2014
Editada: Matt J
el 21 de Mzo. de 2014
No. Make the different Xi the columns of matrix, X and just do A\X.
Más respuestas (0)
Ver también
Categorías
Más información sobre Linear Algebra en Help Center y File Exchange.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!