Create a matrix of binary numbers generated by sequence

I want to create a general matrix to create outputs of the below format...

if n=1
   output=[1 0]

if n=2
  output=[1 1
          1 0
          0 1
          0 0]

if n=3
output=[1 1 1
       1 1 0
       1 0 1 
       1 0 0
       0 1 1
       0 1 0
       0 0 1
       0 0 0]

for any number of n; the output matrix will be of the order of [2^n X n]

Answer 1

[the cyclist]

output = dec2bin(2^n-1:-1:0)-'0'

[Mohammed]

Thankyou very much..can't believe it could be solved in one line!!

[salma ahmed]

thanks alot :)

[poornimasre jegan]

thank you very much. but it is not works when n is large.what should i do if n is more than 30 or 40 etc..?

[Ben Krämer]

Thank you very much!

I am quite new to MATLAB and trying to figure out how I can add constraints to your solution.

What I am trying to get, is a Matrix of all the solution for n=8 that contain at least 5 1s.

I hope someone can help me out here.

[Bruno Luong]

@Kramer, please open a new thread.

[Saber Rahbarfam]

Hello,

Can you please explain what is '0' in this code: output = dec2bin(2^n-1:-1:0)-'0', and what is it doing?

Thanks

Saber

[S]

Thank you, 'the cyclist'. That was very clever.

[Sodamn Insane]

The -'0' converts the output of dec2bin from a character array with each combination as a row element to a matrix with the type of double.

[Muhammad Atif Ali]

this - '0' was the whole trick. I wasted more than 2 hours trying to figure this out.

Answer 2

[Azzi Abdelmalek]

n=3;
s=0:1;
idx=rem(nchoosek(0:2^n-1,n),2)+1;
out=flipud(unique(s(idx),'rows'))

[Mohammed]

Thank you so much.that was quick n short

Answer 3

[görkem tatar]

y =dec2bin(x)

x = 'dec variable'

y = 'convertion of the dec variable to bin'