I have a=[1 2 5 4 2 7 4 8 2 3](10 values),b=[0 1 2 3],I want to fill a so that
a=[0 1 2 3 0 0 0 0 0 0],

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dpb
dpb el 9 de Abr. de 2014

0 votos

There's nothing left so there's no point in doing anything except sotoo--
a=0; a(1:length(b))=b;
a=[b zeros(1,length(a)-length(b)];
An essentially innumerable ways to get there, choose one and go on.

3 comentarios

yousef Yousef
yousef Yousef el 9 de Abr. de 2014
It is not working
dpb
dpb el 9 de Abr. de 2014
so fix the typo of I forgot that '0' is a scaler and won't fill...
a=zeros(size(a)); a(1:length(b)=b;
surely that's not too tough.
yousef Yousef
yousef Yousef el 9 de Abr. de 2014
its perfect.Thanks a lot

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yousef Yousef
yousef Yousef el 9 de Abr. de 2014

0 votos

assume I have d=[1 3 5 6 7 8 1 4 5 10],e=zeros(5,10),I want to take only the first 4 elements of d and fit them to the first row of e

1 comentario

dpb
dpb el 9 de Abr. de 2014
Basically the same thing--just use colon operator to address the elements of concern ensuring the LHS and RHS have same length of subscripting.
All of these kinds of operations are in the "Getting Started" section of the documentation under array addressing. I suggest working thru those early sections and the exercises/examples therein to get the basics down.

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dpb
el 9 de Abr. de 2014

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