Interpreting varargin name-value pairs.
Mostrar comentarios más antiguos
I've been writing a lot of functions lately. I like allowing the user to declare options in my functions using name-value pairs, but I have not found a good clean method of interpreting varargin. Here are two methods I tend to use, but both feel a bit clunky:
% Method 1:
for k = 1:length(varargin)
if strcmpi(varargin{k},'fontname')
fontname = varargin{k+1};
varargin{k+1}=[];
varargin{k}=[];
end
end
% Method 2:
nk = 1:length(varargin);
for k = 1:length(varargin)
if strcmpi(varargin{k},'fontsize')
fontsize = varargin{k+1};
nk(k:k+1) = [];
end
end
varargin = varargin(nk);
Is there a better standard procedure for interpreting a list of varargin arguments?
1 comentario
per isakson
el 2 de Mayo de 2014
Respuesta aceptada
Más respuestas (3)
Kevin Schroeder
el 20 de Jul. de 2021
If it is of any value to others, I have always used a switch case nested in a for loop.
function myFunction(varargin)
for setting = 1:2:nargin
switch varargin{setting}
case 'SettingName1'
value = varargin{setting + 1}
[]; %do stuff with value
case 'SettingName2'
value = varargin{setting + 1}
[]; %do stuff with value
case 'SettingName3'
value = varargin{setting + 1}
[]; %do stuff with value
otherwise
[];
end
end
end
Functionally it should be similar to the nested if statements, but it looks much cleaner.
Justin
el 1 de Mayo de 2014
I'm always a fan of cellfun.
inputExist = find(cellfun(@(x) strcmpi(x, 'fontname') , varargin));
if inputExist
fontsize = varargin{inputExist+1};
end
I have used this or something similar before. You can wrap this in a for loop that goes through your expected inputs and instead of assigning them directly to fontsize you could assign it to a structure like:
inputs.(currentName) = varargin{inputExist+1};
Let me know if that makes sense.
1 comentario
STRCMPI does work on cell arrays, so there is no need to use CELLFUN. Yet, it is likely not to be suited here, because Chad would have to test for all possible parameter names for both the function and the internal function. Using the parser and its Unmachted property is more flexible for this reason.
Alexander
el 17 de Jul. de 2016
0 votos
Dont use inputParser if you need to codegen - it is not supported in R2016a.
1 comentario
Sean de Wolski
el 19 de Jul. de 2016
With codegen, you won't be using variable number of inputs since everything needs to be defined.
Categorías
Más información sobre Argument Definitions en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!