Solve a non linear differential equation systems with only boundary conditions

4 visualizaciones (últimos 30 días)
Hi everybody,
I am currently trying to solve a differential equation of the form :
function dy= myfun(r,y)
N=200e3;
g=1.6861;
dy=zeros(2,1);
dy(2)=y(1).*r.*(N*pi/60)^2;
dy(1)=(y(1)./(g.*y(2))).*y(1).*r.*(N*pi/60)^2;
end
Only , I know from my physical problem only what happened on the edge (at r2=10mm). I tried then to use bvp4c, but I have the feeling they would need anyway at least one initial condition.
guess=[val1;val2];
solinit=bvpinit(linspace(0,r2),40),guess)
sol=bvp5c(@interdisc_space_compressible,@bc,solinit)
where val1=y1(0) et val2=y2(r2) However, I would like to set val1=y1(r2) and val2=y2(r2) instead!
Any hint??
Thanks!!!

Respuestas (1)

Bill Greene
Bill Greene el 6 de Mayo de 2014
You have a system of two first order differential equations so you need just two boundary conditions. I would guess that specifying y1(r2) and y2(r2) is fine.
What kind of problem are you running into? If you post your complete example, we might be able to help.
Bill

Categorías

Más información sobre Partial Differential Equation Toolbox en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by