A grouping vector numbers
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Hello friends I have one matrix and I need assemble all entries of a matriz in one single vector. This I've done. But I need i need extract repeated values of this and put them in new one. For this I need construct a histogram, and verify which values who not equal to zero and increment a count. So if I find a value not equal to zero I have to increment +1 to value (color) in the histogram position. with intervals100 or 200 to perform small increment in the same "color" (value) on vector
A=[1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0;1 2 3 4 5; 2 3 4 5 5; 6 7 8 9 0]
v = reshape( A.' ,1,numel(A));
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dpb
el 19 de Jun. de 2014
I can't really parse the request but on an off chance it'll help...
BTW, the shortcut for reshape(x,1,[]) is
v=A(:); % this works for all array sizes to generate a column vector
Anyway, as said, taking a guess on the question...
n=histc(v,unique(v));
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Biza Ferreira
el 19 de Jun. de 2014
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dpb
el 19 de Jun. de 2014
Did you not try the previous response???? That's precisely what it returns.
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