How do I extract consecutive numbers from a matrix?
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Simo
el 24 de Jun. de 2014
Comentada: Carlene Horner
el 18 de Jun. de 2019
I have a matrix like: A=[1 2 5 6 7 8 9 20 21 22 23…] I'd like to separate consecutive number, like: C=[1 2] D=[5 6 7 8 9], E=[ 20 21 22 23]
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Cedric
el 24 de Jun. de 2014
Editada: Cedric
el 24 de Jun. de 2014
Here is a solution, but there are many ways to do it, some simpler than others:
grouped = mat2cell( A, 1, diff( [0, find(diff(A) ~= 1), length(A)] )) ;
where grouped is a cell array with the following content
>> grouped{1}
ans =
1 2
>> grouped{2}
ans =
5 6 7 8 9
>> grouped{3}
ans =
20 21 22 23
Edit : here is a funny way for Star Strider, who wanted a tutorial about ACCUMARRAY ;-)
grouped = accumarray( cumsum([1, diff(A) ~= 1]).', A, [], @(x){x} ) ;
3 comentarios
Cedric
el 24 de Jun. de 2014
I was actually unaware that ACCUMARRAY could output cell arrays until I learned that from one of Andrei's solutions that blew my mind away.
Carlene Horner
el 18 de Jun. de 2019
I keep getting a horzcat error. I'm assuming this is because when finding the difference of a vector, the length of that difference vector is one less of the original vector. How do you fix this? Thanks!
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