Complicated Question / String Arrays

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Max Müller
Max Müller el 24 de Jul. de 2014
Comentada: dpb el 24 de Jul. de 2014
Hey Guys, i have an array of strings which looks like this:
'J_012(105)' 'J_013(106)' 'J_014(107)' 'J_015(2)' J_016(94)' 'J_017(95)'
But I need it to look like this:
'J_012' 'J_013' 'J_014' 'J_015' 'J_016' 'J_017'
So That the ALWAYS the last 4Strings are deleted/kill. Is this possible ?

Respuesta aceptada

dpb
dpb el 24 de Jul. de 2014
new= cellfun(@(x) x(1:5),old,'uniformoutput',false);
  2 comentarios
Max Müller
Max Müller el 24 de Jul. de 2014
Thanks..both ways wokr
dpb
dpb el 24 de Jul. de 2014
If the pattern isn't fixed length, then regexp is useful; if it is then it's overkill...good to see both

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Más respuestas (1)

Azzi Abdelmalek
Azzi Abdelmalek el 24 de Jul. de 2014
A={'J_012(105)' 'J_013(106)' 'J_014(107)' 'J_015(2)' 'J_016(94)' 'J_017(95)'}
B=cellfun(@(x) x{1} ,regexp(A,'.+(?=\()','match'),'un',0)

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