Need help with this Matlab script question? For loop!!

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Dylan Flores
Dylan Flores el 29 de Jul. de 2014
Editada: Dylan Flores el 29 de Jul. de 2014
I keep getting this error 'Attempted to access x(3); index out of bounds because numel(x)=2.' It's really frustrating!!!

Respuesta aceptada

ES
ES el 29 de Jul. de 2014
You have to define x(3) as well (It should be 2 right ?), and then run the loop from x=3 and change the order of statements inside the while loop, because you set x(k) and then increment k. so for the new incremented k, x(k) will not be defined yet.
Please check:
%%Determining the golden ratio in a fibonacci sequence clear,clc % Defining the first two elements in the sequence x(1) = 1;
x(2) = 1;
x(3) = 2;
k = 3;
while (abs(x(k)./x(k-1) - x(k-1)./x(k-2))>0.001)
k = k+1;
x(k) = x(k-1) + x(k-2);
end

Más respuestas (1)

Robert Cumming
Robert Cumming el 29 de Jul. de 2014
Editada: Robert Cumming el 29 de Jul. de 2014
It the start of your while loop the condition includes a check on x(3), hence why you get the error.
edit: you could fix it this way:
while true
x(k) = x(k-1) + x(k-2);
k = k+1;
if (abs(x(k)./x(k-1) - x(k-1)./x(k-2))>0.001)
break
end
end

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