Interchange dimensions of cell array and the matrices included in it

Hello.

Assume that I have a cell array as shown below:

Can I convert it to the following form:

I need to interchange the number of columns in the cell with the number of columns in the matrices inside. I was able to do it in few lines. But is there a direct way to make this conversion?

Thanks a lot,

Ahmad Gad

Answer 1

[Turlough Hughes]

Here's one way

temp = vertcat(originalData{:});
D = repmat({zeros(3,27)},1,1000); % preallocate
for ii = 1:1000
    D{ii} = reshape(temp(:,ii),3,27);
end

The approach takes the first column from each matrix in the 1x27 input cell array and concatenates the them making a 3x27 matrix for the first cell of the output; then continues to the second input columns for the second cell in the output, and so on and so forth.

EDIT

You could use splitapply as follows:

D = splitapply(@(x) {reshape(x,3,27)}, vertcat(originalData{:}), 1:1000);

Actually, much simpler is not orgainsing the data into cells in the first place - you can have a 3 by 27 by 1000 matrix and this is just easier to work on in the long run:

D = reshape(vertcat(originalData{:}),3,27,1000);

[Ahmad Gad]

Hello Turlough,

I actually wrote it in two lines. I was looking for an even simpler code and function that is dedicated for this job.

Thanks anyway.

Ahmad

[Ahmad Gad]

Hello,

I will check this. I acutally don't look for effeciency in the current application.

Thanks a lot

Ahmad

[Turlough Hughes]

Ok I've added in a one-liner (see edit above). Other than that, I doubt there are more direct functions for what you want to do.