what correction is required in the code?

I am trying to perform 2*2 + 2*5 + 5*8, for [2 2 5 8] vector which is product of consicutive and sum of all. without using sum() & diff() and using for loop
function [out] = pairprodsum (m)
s = 0
for i = 1
b = m(1:end-1).*m(2:end);
s = s + b;
end
out = s;

Respuestas (2)

James Tursa
James Tursa el 11 de Nov. de 2021

0 votos

If the homework assignment specifies you must use a loop, then I don't think the intent was for you to wrap a simple i=1 range around vectorized code. That being said, I suppose your "loop" technically qualifies.
b is a vector. You simply need to sum all the elements of b and return that. s = s + b does not sum the element of b ... it simply creates a new vector s that is a copy of b. You need different code to sum the elements of b. There are various ways to do this, which I will let you figure out.

4 comentarios

Manav Divekar
Manav Divekar el 11 de Nov. de 2021
can you give some hints?
Walter Roberson
Walter Roberson el 11 de Nov. de 2021
s+b(i)
Manav Divekar
Manav Divekar el 11 de Nov. de 2021
its just gives sum of only first postion of the arrey.
James Tursa
James Tursa el 11 de Nov. de 2021
How could you maybe change the for loop range so it added up all of the elements?
Jan
Jan el 11 de Nov. de 2021
Editada: Jan el 11 de Nov. de 2021

0 votos

A hint: You want to perform this:
  • s = 0
  • s = s + 2*2
  • s = s + 2*5
  • s = s + 5*8
You need to loop over the indices of m. There is 1 iteration less than the number of elements of m.

La pregunta está cerrada.

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el 11 de Nov. de 2021

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