Unable to understand the error

1 view (last 30 days)
Mehul kumar
Mehul kumar on 19 Nov 2021
Answered: Akash Singh on 7 Dec 2021
close all
clc
syms c1 c2 x m omega gamma Fo
F=input('enter the coefficients [a,b,c]:');
f=input('enter the RHS function f(x):');
a=F(1);b=F(2);c=F(3);
AE=a*m^2+b*m+c;
m=solve(AE);
m1=m(1);m2=m(2);
D=b^2-4*a*c;
if(D>0)
y1=exp(m1*x);
y2=exp(m2*x);
elseif (D==0)
y1=exp(m1*x);y2=x*exp(m1*x);
else
alfa=real(m1);beta=imag(m1);
y1=exp(alfa*x)*cos(beta*x);
y2=exp(alfa*x)*sin(beta*x);
end
yc=c1*y1+c2*y2;
fx=f/a;
W=y1*diff(y2,x)-y2*diff(y1,x);
u=int(-y2*fx/W,x);
v=int(y1*fx/W,x);
yp=y1*u+y2*v;
y_gen=yc+yp;
check=input('If the problem has initial conditions then enter 1 else enter 2:');
if(check==1)
cn=input('Enter the initial conditions[x0,y(x0),Dyx(0)]:');
dy_gen=diff(y_gen);
eq1=(subs(y_gen,x,cn(1))-cn(2));
eq2=(subs(dy_gen,x,cn(1))-cn(3));
[c1,c2]=solve(eq1,eq2);
y=simplify(subs(y_gen));
disp('The complete solution is');
disp(y);
fplot(y,[cn(1),cn(1)+2]);
else
y=simplify(y_gen);
disp('The general solution is');
disp(y);
end
ERROR
Conversion to logical from sym is not possible.
Error in onetwothree (line 12)
if(D>0)
  2 Comments
Mehul kumar
Mehul kumar on 19 Nov 2021
inputs are
[1,0,omega*omega]
Fo*sin(gamma*x)
[0,0]

Sign in to comment.

Answers (1)

Akash Singh
Akash Singh on 7 Dec 2021
As you mentioned your input is [1,0,omega*omega] which makes value of a, b, c as 1, 0 and omega*omega respectively.
Omega is a sym, which makes c a sym.
In this line of code
D=b^2-4*a*c;
D is also sym
Please note, sym is not a function. It will not evaluate and assign a result to D.
if(D>0)
So, when you compare D(sym) with 0 (double), system throws error because sym can’t be compared to a numeric value.
If you really want to compare D with 0, you will have to first substitute the value of 'omega' in D. The way to do that is by using subs, which will substitute the value.
You can do something like -
if(double(subs(D, yourvalue))>0)
Please refer a similar answered question below -

Products


Release

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by