itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr)=[sin(t) cos(t)];
end
In the above code , I am getting the error " Unable to perform assignment because the indices on the left side are not compatible with the size of the right side."
Please tell me how to fix.

 Respuesta aceptada

Chunru
Chunru el 11 de Dic. de 2021
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr, :)=[sin(t) cos(t)]; % Two numbers for each iteration form a row for a matrix b (nitr x 2)
end
b
b = 3×2
0.8415 0.5403 0.9093 -0.4161 0.1411 -0.9900

4 comentarios

SANDIPKUMAR ROYADHIKARI
SANDIPKUMAR ROYADHIKARI el 11 de Dic. de 2021
Thank you
SANDIPKUMAR ROYADHIKARI
SANDIPKUMAR ROYADHIKARI el 12 de Dic. de 2021
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr, :)=[sin(t) cos(t)];
c(itr, :)=[1-sin(t) 1];
d(itr,:)=[b;c];
end
I get this error------Unable to perform assignment because the indices on the left side are not compatible with the size of the right side.
Please help
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr, :)=[sin(t) cos(t)];
c(itr, :)=[1-sin(t) 1];
end
d=[b c]
d = 3×4
0.8415 0.5403 0.1585 1.0000 0.9093 -0.4161 0.0907 1.0000 0.1411 -0.9900 0.8589 1.0000

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R2021b

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el 11 de Dic. de 2021

Comentada:

el 12 de Dic. de 2021

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