# Plot a function for x<0 and x >0

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RandomChikiBum el 25 de Dic. de 2021
Comentada: Simon Chan el 26 de Dic. de 2021
The assigned task is to make a triangular function with peak amplitude of 1 over -5 to +5 without any inbuilt functions.
My approach was to use the respective line equation for x>0 and x<0, but I didn't kow how to do it.
Any other approach to this problem is also appreciated.
Edit:- for some clarity, we are not supposed to use functoins like "Saw-tooth" in this case. while functions like ones,zeroes,plot are fine
The following is my code for the approach I have mentioned above, Any othe approaches are also welcomed
And does anyone know why the title,xlabel,ylabel are not being showed in the output?'
Thanks!
x = (0: 1:5);
k = (-5 :1 :0);
grid on;
g = (k/5) + 1;
y =(-x/5) + 1;
title('Task-2 Triangular Signal');
xlabel('Time');
ylabel('Amplitude');
plot(x,y,k,g);
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Walter Roberson el 26 de Dic. de 2021
When you call plot() or most other graphics calls, if you have not called
hold on
or equivalent, then the first thing plot will do is locate the axes and cla() the axes.
Move the labels and title to after the plot call.
RandomChikiBum el 26 de Dic. de 2021
Thanks @Walter Roberson will keep this in mind the next time I code!

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### Respuesta aceptada

Simon Chan el 26 de Dic. de 2021
You may modify based on the following code and you should plot first and then set the grid,title,xlabel,ylabel,etc
x = -5:5;
y = 1-abs(x/5);
plot(x,y);
grid on;
title('Task-2 Triangular Signal');
xlabel('Time');
ylabel('Amplitude');
##### 5 comentariosMostrar 3 comentarios más antiguosOcultar 3 comentarios más antiguos
RandomChikiBum el 26 de Dic. de 2021
@Simon Chan can you post another answer with the logical operators , so that I can accept the answer?
Simon Chan el 26 de Dic. de 2021
You can just simply accept this answer, glad it solve your question.

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