how to add one space to a matrix ?

2 visualizaciones (últimos 30 días)
janny
janny el 9 de Nov. de 2014
Comentada: janny el 10 de Nov. de 2014
am using this code to generate binary matrix dec2bin(rand(50,1)*2^32) but i need to add one space between the matrix element so i can use it for other commands. the output matrix needs space to be useful for other calculation. how to do this?

Respuesta aceptada

Guillaume
Guillaume el 9 de Nov. de 2014
Editada: Guillaume el 9 de Nov. de 2014
The following would work:
m = dec2bin(rand(50,1)*2^32)
mwithspaces = cell2mat(regexprep(num2cell(m, 2),'\d(?=\d)', '$0 '));
I have to ask though, why do you want to do that? It seems like an unnecessary step. I would think that any algorithm that follows is probably going to remove these spaces one way or another.
edit: was missing a bracket
  5 comentarios
Guillaume
Guillaume el 9 de Nov. de 2014
As commented on Jan's answer, inserting spaces is a red herring. To convert a string of zeros and ones into a matrix of zeros and ones numbers, simply subtract '0' from the string.
This may be what you're looking for:
M = dec2bin(rand(10, 1) * 2^32);
M = M - '0'; %convert M into an array of numbers 0 or 1
[m, n] = size(M);
M2 = [zeros(m, 3*ceil(n/3)-n), M];
X = xor(xor(M2(:, 1:3:end-2), M2(:, 2:3:end-1)), M2(:, 3:3:end))
janny
janny el 10 de Nov. de 2014
it works fine... thanks a lot....

Iniciar sesión para comentar.

Más respuestas (2)

Jan
Jan el 9 de Nov. de 2014
Editada: Jan el 9 de Nov. de 2014
s = dec2bin(rand(50,1)*2^32);
t = repmat(' ', size(s, 1), size(s, 2) * 2 - 1);
t(:, 1:2:end) = s;
  2 comentarios
janny
janny el 9 de Nov. de 2014
Editada: janny el 9 de Nov. de 2014
i'm writing an algorithm to calculate CA rule 150 from this sequence, so when i try these codes didn't give the right answer, this is my code:
M = dec2bin(rand(10,1)*2^32);
[m,n] = size(t);
M2 = [zeros(m,3*ceil(n/3)-n),t];
X = xor(xor(M2(:,1:3:end-2),M2(:,2:3:end-1)),M2(:,3:3:end))
if : M = [0 0 0 1 1 1 1 1 1 0 1 1 1 0 1 0 0 0 0 0 0 1 1 0 1 0 0 1 0 1 1 1]
then X = 0 0 1 0 0 1 0 0 1 1 1
so how to make it run?
Guillaume
Guillaume el 9 de Nov. de 2014
Editada: Guillaume el 9 de Nov. de 2014
I don't know what CA rule 150 is so why don't you explain it.
It is now clear however, that your original question is a case of xy problem. Looking at your attempted code, you don't need to insert spaces and actually want to operate on numbers rather than strings.
xor certainly does not work with strings.
See comment on my own answer for a possible solution.

Iniciar sesión para comentar.


yonatan gerufi
yonatan gerufi el 9 de Nov. de 2014
see in the "file exchange" :
  3 comentarios
yonatan gerufi
yonatan gerufi el 9 de Nov. de 2014
perhaps i misunderstood you.
the code : dec2bin(rand(50,1)*2^32)
gives you string of ones & zeros. you can pad it with ' ' (space), and then you will have space between the elements.
Image Analyst
Image Analyst el 9 de Nov. de 2014
It gives a 2D character array, not a simple string. I think maybe he wants all those rows concatenated together with a space in between them.

Iniciar sesión para comentar.

Categorías

Más información sobre Characters and Strings en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by