# Quadratic Optimization for 4D in for Loop

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MarshallSc el 31 de Dic. de 2021
Comentada: yanqi liu el 1 de En. de 2022
I need to find the roots (complex in nature) of an objective function in 4D by using quadratic optimization for the function below:
a = [0.0068 0.0036 0.000299 0.0151]; b = [0.0086 0.00453 0.0016 0.00872]
f = @(xj,xk) a(i) - (x(j)*x(k)) * b(l); %i,j,k,l = 1:4 - simple eqn: f = @(x1,x2) a(1) - (x(2)*x(3)) * b(4)
The problem that I have is that I don't know how to write it in a for loop or permutation manner that each loop takes a specific value of the (a,b) and (xj,xk) from 1:4. Basically it's a nonlinear coordinate transformation. Since my X(i) * X(j) makes the problem quadratic, I need to perform an approximation using the only equality constraint such (imposing the symmetry of the potential function - (i,j) and (k,l) pair become exchangeable):
(x(j)*x(k)) * b(l) + (x(i)*x(l)) * b(k) + (x(k)*x(j)) * b(j) + (x(l)*x(i)) * b(i) =< a(i) + a(j) + a(k) + a(l)
That's my only constraint for optimization that minimizes the objective function. I tried using fmincon but I don't know how to use it in a loop for the equation and the constraint.
I'd appreciate it if someone can help me! Thank you!
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yanqi liu el 31 de Dic. de 2021
yes，sir，may be write the equations，and we can use loop to generate cmd string，then use eval to get function handle

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yanqi liu el 31 de Dic. de 2021
clc; clear all; close all;
a = [0.0068 0.0036 0.000299 0.0151];
b = [0.0086 0.00453 0.0016 0.00872];
% f = @(xj,xk) a(i) - (x(j)*x(k)) * b(l); %i,j,k,l = 1:4 - simple eqn: f = @(x1,x2) a(1) - (x(2)*x(3)) * b(4)
for i = 1 : length(a)
eqi = sprintf('f=@(x1,x2) %f- (x(1)*x(2))*%f;', a(i), b(i));
disp(eqi)
end
f=@(x1,x2) 0.006800- (x(1)*x(2))*0.008600; f=@(x1,x2) 0.003600- (x(1)*x(2))*0.004530; f=@(x1,x2) 0.000299- (x(1)*x(2))*0.001600; f=@(x1,x2) 0.015100- (x(1)*x(2))*0.008720;
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MarshallSc el 31 de Dic. de 2021
Editada: MarshallSc el 31 de Dic. de 2021
Thanks Yanqi for your answer. Do you know how I can incoporate this pemutated equation to solve for the quadratic optimization to find the minimum values of Xs? a & b are just the coefficient of the second order polynomial.
I'm a little bit lost as to what should be done. I'd appreciate it.
yanqi liu el 1 de En. de 2022
yes，sir，may be it is non-linear optimization，use fmincon to get compute，may be write your equations in handwriting，we can make some debug

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