Equations to Matlab code

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Maria
Maria el 18 de Nov. de 2014
Respondida: Warren Dennis el 17 de Feb. de 2020
hi
I want to convert the two equations below into Matlab code , I wrote the function below for that and I don't know if that is correct or not , specially the integral form ? any help ?
function [VI,Vw]= Modelfun(TL,TR)
dt=0.01; %sampling time
r=0.052;
L=0.306;
M=9;
I=5;
VI=(TL+TR)/ M * r;
VI=VI*dt/2; %first integral
Vw=(L*(TL-TR)) / 2 * r * I;
Vw=Vw*dt/2; %first integral
Vw=Vw*dt/2; %second integral
end

Respuesta aceptada

Torsten
Torsten el 20 de Nov. de 2014
It is not possible simply to output (VI,Vw) given (TL,TR).
As input you need (VIold,Vwold,Vwdotold,dt,TL,TR).
The output VI,Vw and Vwdot is then calculated according to
VI=VIold+dt*(TL+TR)/(M*r)
Vw=Vwold+dt*Vwdotold
Vwdot=Vwdotold+dt*L*(TL-TR)/(2*r*I).
This would mean that your function "Modelfun" advances VI and Vw from their values at time t to time t+dt.
Best wishes
Torsten.

Más respuestas (2)

Torsten
Torsten el 18 de Nov. de 2014
If the right-hand sides of your equations does not depend on t, the solution to your differential equations is explicitely given by
VI=VI0+(TL+TR)/(M*r)*t
Vw=Vw0+Vw0dot*t+0.5*L*(TL-TR)/(2*r*I)*t^2
where
VI0=VI at time t=0
Vw0=Vw at time t=0
Vw0dot = d/dt(Vw) at time t=0.
Best wishes
Torsten.
  5 comentarios
Maria
Maria el 19 de Nov. de 2014
thanks a lot Torsten
Actually , I am not so good with Matlab and from my little bit understanding I built this function and I don't know if that right but generally what I want to do is to write the equations above in code form inside "Embedded MATLAB Function " block with two inputs(TL,TR) and two outputs (VI,Vw) as in figure above.
thanks
Maria
Maria el 20 de Nov. de 2014
???

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Warren Dennis
Warren Dennis el 17 de Feb. de 2020
k=k0e

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