Finding the determinant without det(a)
41 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Ryan Driver
el 27 de En. de 2022
I need to physically computate the determinant of 3x3 matrices and lower without using the det(a) function, rather loops. What's causing this error?
1 comentario
DGM
el 27 de En. de 2022
Editada: DGM
el 27 de En. de 2022
Like Max, I'm guessing that matrix a1 isn't the expected size. In the future, it's best to post the code as formatted code instead of pictures so that people can troubleshoot it.
I'm just going to throw this out there. You can reuse the code for calculating the 2x2 case.
A = rand(3);
DA1 = det(A)
DA2 = det33(A)
function D = det22(A)
D = prod(A([1 4])) - prod(A([2 3]));
end
function D = det33(A)
D = A(1,1)*det22(A(2:3,2:3)) - A(1,2)*det22(A(2:3,[1 3])) + A(1,3)*det22(A(2:3,1:2));
end
Respuesta aceptada
Max Heimann
el 27 de En. de 2022
Editada: Max Heimann
el 27 de En. de 2022
According to the error you are trying to access an index which is not part of the variable.
Are you sure a1 is a 3x3 matrix?
It looks like you are calling the function with a 2x3 matrix [1 2 3; 4 5 6]
Más respuestas (0)
Ver también
Categorías
Más información sobre Linear Algebra en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!