non zero elements in an array

if a=[1 2 4 5 3 0 0 8 0]

how can i make the elements greater than or equal to 2 as 1 and smaller than two as 0.

so that it become like this:

[0 1 1 1 1 0 0 1 0]

Answer 1

[Arif Hoq]

a=[1 2 4 5 3 0 0 8 0];
[idx]=find(a<2);
a(idx)=0;
out=a;
[idx2]=find(out>=2);
out(idx2)=1

out = 1×9

0 1 1 1 1 0 0 1 0

[Catalytic]

This method does not work, so I don't know why it was accepted. a(1) is neither less than 0 nor greater tha or equal to 2. It should remain unchanged.

[Arif Hoq]

a(1)=1 % 1 is < 2

It was asked to find >=2 would be 1 and <2 would be 0

[DGM]

That might be how you read the question, but that's not what it says.

Granted, the OP's example output doesn't match their own requirement either.

[ali hassan]

@DGM@Arif Hoq@Catalytic in haste, i made a mistake.

i have rectified it. i am sorry for it.

i intended to ask the same what @Arif Hoq replied. though in my question, i wrote zero instead of two but i got the concept which was required.

[Matt J]

but i got the concept which was required.

Except that this solution still teaches the regrettably popular habit of using find() in situations where it is unnecessary.

a=[1 2 4 5 3 0 0 8 0];

out=a;
out(a<2)=0;
out(a>=2)=1

out = 1×9

0 1 1 1 1 0 0 1 0

Answer 2

[DGM]

I'm going to assume you're only dealing in integers here, otherwise the question arises whether values between 1 and 2 should really be preserved.

a = [1.5 1 2 4 5 3 0 0 8 0];
b = max(min(a,1),0)

b = 1×10

1 1 1 1 1 1 0 0 1 0

If values between 1 and 2 should be preserved, then:

c = max(a,0);
c(c>=2) = 1

c = 1×10

1.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0 0 1.0000 0

Answer 3

[Matt J]

If a are always integers,

a = [1 2 4 5 3 0 0 8 0];
a=(a>=2)

a = 1×9 logical array
   0   1   1   1   1   0   0   1   0