logical operation on matrix

Update matrix A so that all odd values will be subtracted by 1

 A=[1 2 3;4 5 6; 4 5 2]

A = 3×3

1 2 3 4 5 6 4 5 2

 rem(A,2)-1%WRONG

ans = 3×3

0 -1 0 -1 0 -1 -1 0 -1

Answer 1

[Arif Hoq]

A=[1 2 3;4 5 6; 4 5 2]

A = 3×3

1 2 3 4 5 6 4 5 2

B=rem(A,2)  % returns the odd number

B = 3×3

1 0 1 0 1 0 0 1 0

output=A-B

output = 3×3

0 2 2 4 4 6 4 4 2