how to read text file into formatted array
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H D
el 15 de Dic. de 2014
Comentada: H D
el 15 de Dic. de 2014
Hi
I have a text file which contains many rows of this shape
'0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10'
I need to read each line in different cells. each cell contains data between ";" and the third and forth one are date and time while others are double numbers.
would you please help me to do so
2 comentarios
per isakson
el 15 de Dic. de 2014
Editada: per isakson
el 15 de Dic. de 2014
"I need to read each line in different cells"   Why is that? And what does it exactly mean?
Respuesta aceptada
per isakson
el 15 de Dic. de 2014
Editada: per isakson
el 15 de Dic. de 2014
Here is a function, which does what I believe is what you want. The third column of out is a serial date number.
>> out = cssm('cssm.txt')
out =
1.0e+06 *
0.0009 0.0000 0.7315 0.0000 0.0000 0.4863 4.2076
0.0009 0.0000 0.7315 0.0000 0.0000 0.4863 4.2076
0.0009 0.0000 0.7315 0.0000 0.0000 0.4863 4.2076
>> datestr( out(:,3), 31 )
ans =
2002-10-09 09:15:59
2002-10-09 09:15:59
2002-10-09 09:15:59
where
function out = cssm( filespec )
fid = fopen( filespec );
cac = textscan( fid, '%f%f%s%s%f%f%f%f' ...
, 'Delimiter',';', 'CollectOutput',true );
fclose( fid );
str = cell2mat(cac{2});
sdn = datenum( str, 'mm/dd/yyyyHH:MM:SS');
out = cat( 2, cac{1}, sdn, cac{3} );
end
and where cssm.txt contains
0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10
0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10
0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10
4 comentarios
per isakson
el 15 de Dic. de 2014
Editada: per isakson
el 15 de Dic. de 2014
cssm is the function defined after the word, where, in my answer.
Más respuestas (1)
Azzi Abdelmalek
el 15 de Dic. de 2014
Editada: Azzi Abdelmalek
el 15 de Dic. de 2014
fid=fopen('FileName.txt')
tline = fgetl(fid)
out=[];
while ischar(tline)
out{end+1,1} =tline
tline= fgetl(fid);
end
fclose(fid)
%You can aadd
A=regexp(out,';','split')
n=numel((A{1}))
B=reshape([A{:}],n,[])'
res=[cell
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