symbolic matrix help converting

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grace lim
grace lim el 22 de Mzo. de 2022
Respondida: Star Strider el 22 de Mzo. de 2022
syms j w C R h11 h12 h21 h22
%matrix i would like to solve ABCD=[1 (1/(j*w*C))+R; 0 1]
%formular to converting ABCD to h para
A=((h11*h22)-(h12*h21))/h21
B=-h11/h21
C=-h22/h21
D=-1/h21
ABCD=[A B;C D]
i have problem trying to get a matrix from the original matrix(ABCD=[1 (1/(j*w*C))+R; 0 1])
using the formular
A=((h11*h22)-(h12*h21))/h21
B=-h11/h21
C=-h22/h21
D=-1/h21
please help

Respuestas (1)

Star Strider
Star Strider el 22 de Mzo. de 2022
One problem is that ‘C’ is being used to designate the capacitor, and also the ‘ABCD’ (2,1) element. Designating the capacitor as ‘Cc’ removes that ambiguity —
syms w Cc R h11 h12 h21 h22
%matrix i would like to solve ABCD=[1 (1/(j*w*Cc))+R; 0 1]
%formular to converting ABCD to h para
A=((h11*h22)-(h12*h21))/h21
A = 
B=-h11/h21
B = 
C=-h22/h21
C = 
D=-1/h21
D = 
ABCD=[A B;C D]
ABCD = 
ABCD = simplify(ABCD, 500)
ABCD = 
S = ABCD == [1 (1/(1j*w*Cc))+R; 0 1]
S = 
[h11 h12 h21 h22] = solve(S,[h11 h12 h21 h22])
h11 = 
h12 = 
h21 = 
h22 = 
0
I also removed ‘j’ and replaced it with the imaginary operator ‘1j’ (that now appears as i) for clarity.
.

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