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MATLAB function and symbolic function give different answers

2 visualizaciones (últimos 30 días)
% Some values for the plot
A = 0.5
B = 2
% MATLAB and symbolic functions generated two ways
f = @(a, b, x) (a .* (x - b).^2) .* ((x - b) >= 0)
fsym = sym(f); % Uncommenting this line hangs Live Script
syms a b x
fsym2(a, b, x) = (a * (x - b)^2) * ((x - b) >= 0); % Uncommenting this line hangs Live Script
% Plot both functions
figure
X = (0:0.001:3*B);
subplot(1, 3, 1)
plot(X, f(A, B, X), '-r')
title('MATLAB function')
subplot(1, 3, 2)
plot(X, subs(subs(subs(fsym, sym('a'), A), sym('b'), B), sym('x'), X), '-b')
title('Function from sym')
subplot(1, 3, 3)
plot(X, fsym2(A, B, X), '-b')
title('Declared symbolic function')
I am trying to get better at using symbolic functions. I am struggling to understand why the two symbolic subplots do not appear identical (other than color) to the subplot generated by the MATLAB function. Can someone explain why, and what I would do to create a "working" symbolic version of f?
As an aside, both lines 7 and 9 hangs the Live Editor if uncommented...does that suggest a bug in what I am doing?

Respuesta aceptada

David Hill
David Hill el 5 de Abr. de 2022
A = 0.5;
B = 2;
f = @(a, b, x) (a .* (x - b).^2) .* ((x - b) >= 0);
syms a b x;
fsym1 = piecewise((x-b)>=0,(a * (x - b)^2),(x-b)<0,0);
figure
X = (0:0.001:3*B);
subplot(1, 3, 1)
plot(X, f(A, B, X), '-r')
title('MATLAB function')
subplot(1, 3, 2)
fsym=subs(fsym1,[a b],[A B]);
fplot(fsym,[0,3*B]);
title('Function from sym')
  4 comentarios
Paul
Paul el 6 de Abr. de 2022
Editada: Paul el 6 de Abr. de 2022
The result from fsym2 can be explained as follows. However, there might be something odd going on because the Live editor can't render the result, so I'll copy/paste from my local installation.
syms a z
fsym2 = a*(z>=0);
On the right hand side, 'a' is symbolic varibale and 'z >= 0' is an equation. So the the multiplication by 'a' distributes across the equation as it would in a standard mathematical sense. Recall that multiplying an inequality by a negative number reverses the direction of the inequality. Also, the sign of 'a' is unknown absent any additional assumptions, so multiplying through by 'a' has to account for the cases of a <= 0 and a > = 0. The result is
fsym2 = piecewise(0 <= a, 0 <= a*z, a <= 0, a*z <= 0)
The bottom line is that in Symbolic math 'z >= 0' is a math equation, whereas in base Matab 'z >= 0' is an expression to be evaluated to T/F and then converted to double.
James Akula
James Akula el 20 de Abr. de 2022
Editada: James Akula el 21 de Abr. de 2022
I think this explains it. It is weird behavior though...might catagorize it as a bug. Certainly, the fact that piecewise seems to crash the live editor is a problem!

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