Fast function application

2 visualizaciones (últimos 30 días)
Mateusz
Mateusz el 29 de Sept. de 2011
Hi,
Let a be n-dimensional vector, B n-by-n dimensional matrix, f(a, b) - binary function that operates on two vectors, and returns scalar as a result. Is there fast way (no-loops) to implement application of this function to vector a and every column of matrix B? More precisely forall_j r(j) = f(a, B(:, j))?
  1 comentario
Mateusz
Mateusz el 29 de Sept. de 2011
I think I cannot repmat vector 'a' since f has to work explicitly on vectors.

Iniciar sesión para comentar.

Respuesta aceptada

Walter Roberson
Walter Roberson el 29 de Sept. de 2011
These days, "no loops" is not necessary any faster.
You can use
arrayfun(@(K) f(a,B(:,K)), 1:size(B,2))
but that will probably not be any faster than a loop.

Más respuestas (0)

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by