converting row and column

I have two questions:

• why when I use this code evenif Ic and n are one column matrix, I recieve one row matrix for Kc?
• How can I write the last line that in any array with that condition gives me NC for example?

Ic= real(((3.47-log10(Q)).^2+(1.22+log10(F)).^2).^0.5);

n(Ic<1.64)=.5;

n(Ic>1.64&Ic<3.3)=(Ic(Ic>1.64&Ic<3.3)-1.64)*.3+.5;

Kc(Ic<1.64) = 1.0;

Kc(Ic>1.64&Ic<2.6) = -0.403*(Ic(Ic>1.64&Ic<2.6)).^4+5.581*(Ic(Ic>1.64&Ic<2.6)).^3-21.63*(Ic(Ic>1.64&Ic<2.6)).^2+33.75*(Ic(Ic>1.64&Ic<2.6))-17.88;

Kc(Ic>2.6) = 'NC';

Answer 1

[Torsten]

By default, all one-dimensional vectors are row vectors.

But if you initialize Kc as a column vector, you'll get Kc a column vector:

Kc = zeros(numel(Ic),1);
...

If NC is a number, you can use

Kc(Ic>2.6) = NC

If you want to mark the positions in Kc where Ic is > 2.6, I suggest using NaN:

Kc(Ic>2.6) = NaN

[Mohammad Sadegh Nasirianfar]

thanks a lot!