Solve a numerical function
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I am trying to solve a numerical equation with three unkonown values Ge, G and t , thse values will be approximated by fitting the curve with the from equation (Gp) to the following data obtained.
This means that is possible to make a curve approximation in order to know the values of the G anf t terms, depending on the number of terms desired for the sum.
I would really appreciate if someone could help me please. Here is the code and the data:
clear all, close all
data1=[0.010931641 0.011369615 0.012298683];
data2=[691.5802655 719.3455778 778.7159258];
Gp=data2(1); wp=data1(1);
for i=1:11
Gp=Ge+(G(i)*wp^2*t(i)^2)/(1+wp^2*t(i)^2)
end
3 comentarios
Sam Chak
el 27 de Mayo de 2022
You have 3 unknown variables, but only 1 equation to describe the relationship. Can you provide more information about the problem?
Gp = Ge + (G*wp²*t²)/(1 + wp²*t²)
(Gp – Ge)*(1 + wp²*t²) = G*wp²*t²
(Gp – Ge)*(1/(wp²*t²) + 1) = G
Walter Roberson
el 27 de Mayo de 2022
It is a curve fitting problem. You can solve for three variables if you have 3 or more points, each of which generates an implicit equation.
issam BEN SALAH
el 27 de Mayo de 2022
Respuestas (1)
Sam Chak
el 28 de Mayo de 2022
Hi Issam
From the advice of Mr. Roberson, you can create 3 equations from the data points:
691.5802655 = Ge + (G*0.010931641²*t²)/(1 + 0.010931641²*t²);
719.3455778 = Ge + (G*0.011369615²*t²)/(1 + 0.011369615²*t²);
778.7159258 = Ge + (G*0.012298683²*t²)/(1 + 0.012298683²*t²);
and then solve them simultaneously to obtain the solutions for the 3 variables:
Ge ≈ 260.642
G ≈ 2166.56
t ≈ ±45.5822
5 comentarios
issam BEN SALAH
el 29 de Mayo de 2022
Sam Chak
el 29 de Mayo de 2022
Hi Issam
If you have 11 equations (required to solve for 11 variables), then you can use the code involving the fsolve function as shown here:
Else, you can consult with Mr. @Walter Roberson if there is a better way for solving for 11 variables.
issam BEN SALAH
el 29 de Mayo de 2022
I only see two solutions.
In any case, why do you think that is an error?
syms Ge G1 t1 G2 t2;
w=[0.010931641 0.011369615 0.012298683];
Gp=[691.5802655 719.3455778 778.7159258];
E1= (Ge - Gp(1) + (G1*t1^2*w(1)^2)/(t1^2*w(1)^2 + 1)+(G2*t2^2*w(1)^2)/(t2^2*w(1)^2 + 1));
E11=(- Gp(1) + (G1*t1^2*w(1)^2)/(t1^2*w(1)^2 + 1)+(G2*t2^2*w(1)^2)/(t2^2*w(1)^2 + 1));
E2=(Ge - Gp(2) + (G1*t1^2*w(2)^2)/(t1^2*w(2)^2 + 1)+(G2*t2^2*w(2)^2)/(t2^2*w(2)^2 + 1));
E22=(- Gp(2) + (G1*t1^2*w(2)^2)/(t1^2*w(2)^2 + 1)+(G2*t2^2*w(2)^2)/(t2^2*w(2)^2 + 1));
E3=(Ge - Gp(3) + (G1*t1^2*w(3)^2)/(t1^2*w(3)^2 + 1)+(G2*t2^2*w(3)^2)/(t2^2*w(3)^2 + 1));
E33=(- Gp(3) + (G1*t1^2*w(3)^2)/(t1^2*w(3)^2 + 1)+ (G2*t2^2*w(3)^2)/(t2^2*w(3)^2 + 1));
sol = solve(E1,E11,E2,E22,E3,E33, Ge, G1, t1, G2, t2)
vpa(subs([Ge, G1, t1, G2, t2], sol))
issam BEN SALAH
el 30 de Mayo de 2022
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